9.7 Implement the "paint fill" function that one might see on many image editing programs. That is, given a screen (represented by a two-dimensional array of colors), a point, and a new color, fill in the surrounding area until the color changes from the original color.

 

这道题是一道填充问题，有点类似于Flash中的油桶工具，就是给指定的位置填充颜色，如果要填充的颜色和原来的颜色相同，则不发生变换，如果不同的话，则把相连接的区域都填充为新的颜色。那么我们使用递归来做，首先判断要填充的颜色和该位置上原有的颜色是否相同，如果不同的话就开始填充，如果周围颜色和起始位置颜色相同也填充，参见代码如下：

 

enum Color { Black, White, Red, Yellow, Green };

class Solution {

public:

bool paintFill(vector > &screen, int x, int y, Color newColor) {

if (screen[x][y] == newColor) return false;

return paintFill(screen, x, y, screen[x][y], newColor);

}

bool paintFill(vector > &screen, int x, int y, Color oldColor, Color newColor) {

if (x < 0 || x >= screen.size() || y < 0 || y >= screen[0].size()) return false;

if (screen[x][y] == oldColor) {

screen[x][y] = newColor;

paintFill(screen, x - 1, y, oldColor, newColor);

paintFill(screen, x + 1, y, oldColor, newColor);

paintFill(screen, x, y - 1, oldColor, newColor);

paintFill(screen, x, y + 1, oldColor, newColor);

}

return true;

}

};

 

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